import itertools

alphabet = "ЕГЭ"

vol = "ЕЭ"

ar = itertools.product(alphabet, repeat = 5) #Раз­ме­ще­ние с по­вто­ре­ни­ем

arl = []

for i in ar:

arl.append(list(i))

count = 0

for e in arl:

if e[0] in vol:

count += 1

print(count)

from itertools import *

cnt = 0

for per in product('ЕГЭ', repeat=5):

slovo = ''.join(per)

if slovo[0] in 'ЕЭ':

cnt += 1

print(cnt)

from itertools import product

print([m[0] != 'Г' for m in product('ЕГЭ', repeat=5)].count(True))

import itertools

alphabet = "ЗИМА"

con = "ЗМ"

vol = "ИА"

ar = itertools.product(alphabet, repeat=5) #Раз­ме­ще­ние с по­вто­ре­ни­ем

arl = []

for i in ar:

arl.append(list(i))

count = 0

for e in arl:

if e[0] in con and e[-1] in vol:

count += 1

print(count)

count = 0

for i1 in 'ЗИМА':

for i2 in 'ЗИМА':

for i3 in 'ЗИМА':

for i4 in 'ЗИМА':

for i5 in 'ЗИМА':

s = i1 + i2 + i3 + i4 + i5

if (s[0] == 'З' or s[0] == 'М') and (s[4] == 'И' or s[4] == 'А'):

count += 1

print(count)

from itertools import product

count = 0

for i in product('ЗИМА', repeat=5):

s = ''.join(i)

if (s[0] == 'З' or s[0] == 'М') and (s[4] == 'И' or s[4] == 'А'):

count += 1

print(count)

from itertools import *

words = [''.join(i) for i in product(sorted('ЗИМА'), repeat=5) if (i[0] in 'ЗМ') and (i[-1] in 'ИА')]

print(len(words))

import itertools

count = 0

for i in itertools.product("СЛОН", repeat=5):

arl = ''.join(i)

if arl.count('С') == 1:

count += 1

print(count)

import itertools

alphabet = "ПИР"

ar = itertools.product(alphabet, repeat=5) #Раз­ме­ще­ние с по­вто­ре­ни­ем

arl = []

for i in ar:

arl.append(list(i))

count = 0

for e in arl:

if e.count('П') == 1:

count += 1

print(count)

import itertools

print(len([p for p in itertools.product('ПИР',repeat = 5) if p.count('П') == 1]))

import itertools

alphabet = "ABCX"

ar = itertools.product(alphabet, repeat=5) #Раз­ме­ще­ние с по­вто­ре­ни­ем

arl = []

for i in ar:

arl.append(list(i))

count = 0

for e in arl:

if (e[0] == 'X' or e[0] != 'X') and e[1] != 'X' and e[2] != 'X' and e[3] != 'X' and e[4] != 'X':

count += 1

print(count)

from itertools import *

cnt = 0

for i in product('ABCX', repeat=5):

p = ''.join(i)

if p.count('X') < 2 and p[0] == 'X' or p.count('X') == 0:

cnt +=1

print(cnt)