def f(x,a):

return ((x&5160 > 0) or (x&3650>0)) <= ((x&9545 == 0) <= (x&a >0))

for a in range(10**5):

if all(f(i,a) for i in range(10**5)):

print(a)

break

m = []

for a in range (0,20000):

count = 0

for x in range (0,100000):

if (((x&6280) > 0) or ((x&3394) > 0)) <= (((x&10828) == 0) <=((x&a) > 0)):

count += 1

else:

break

if count == 100000:

m.append(a)

print(min(m))