a = {0: "А", 1: "О", 2: "У"}

k = 0

for i in range(0, len(a)):

for j in range(0, len(a)):

for g in range(0, len(a)):

for m in range(0, len(a)):

for n in range(0, len(a)):

k += 1

if a[i] == "У":

print(k) # Возь­мем пер­вое число, ко­то­рое вы­ве­дет про­грам­ма

break

alf = 'АОУ'

count = 0

for x1 in alf:

for x2 in alf:

for x3 in alf:

for x4 in alf:

for x5 in alf:

slovo = x1 + x2 + x3 + x4 + x5

count += 1

if x1 == 'У':

print(count, slovo)

exit()

from itertools import product

c = 0

s = product('АОУ', repeat = 5)

for i in s:

p = ''.join(i)

c += 1

if p[0] == 'У':

print(c)

break

a = {0: "А", 1: "О", 2: "У"}

k = 0

for i in range(0, len(a)):

for j in range(0, len(a)):

for g in range(0, len(a)):

for m in range(0, len(a)):

for n in range(0, len(a)):

k += 1

if a[i] == "О":

print(k) # Возь­мем пер­вое число, ко­то­рое вы­ве­дет про­грам­ма

break

from itertools import product

for i, p in enumerate(product(sorted('АОУ'), repeat=5)):

if p[0] == 'О':

print(i+1)

break