from itertools import product

count = 0

for p in product("012345678", repeat=7):

if p.count("6") == 1 and p[0]!="0" and(p.count("1")+p.count("3") + p.count("5") + p.count("7"))==2:

count+=1

print(count)

k = 0

for i1 in '12345678':

for i2 in '012345678':

for i3 in '012345678':

for i4 in '012345678':

for i5 in '012345678':

for i6 in '012345678':

for i7 in '012345678':

p = i1+i2+i3+i4+i5+i6+i7

if p.count('6') == 1 and (p.count('1') + p.count('3') + p.count('5') + p.count('7'))==2:

k += 1

print(k)