n = 7 * (512 ** 1912) + 6 * (64 ** 1954) - 5 * (8 ** 1991) - 4 * (8 ** 1980) - 2022

print(oct(n).count('7'))

x = 7 * (512 ** 1912) + 6 * (64 ** 1954) - 5 * (8 ** 1991) - 4 * (8 ** 1980) - 2022

s = ""

while x != 0:

s += str(x % 8)

x //= 8

s = s[::-1]

print(s.count("7"))